提交记录 11979
| 提交时间 |
评测时间 |
| 2020-03-05 13:01:03 |
2020-08-01 02:49:58 |
#include <algorithm>
unsigned int t[1005]; // 归并排序的常见实现中, 需要一个临时数组用于归并结果
void mergesort(unsigned int a[], int l, int r) {
if (l >= r) return;
int mid = (l + r + 1) >> 1;
mergesort(a, l, mid);
mergesort(a, mid, r);
int p = l, q = mid, s = l;
while (s <= r) {
if (p >= mid || (q <= r && a[p] > a[q])) {
t[s++] = a[q++];
} else t[s++] = a[p++];
}
for (int i = l; i <= r; ++i) a[i] = t[i];
}
void sort(unsigned *a, int n) {
mergesort(a, 0, n-1);
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 65.265 ms | 511 MB + 996 KB | Runtime Error | Score: 0 | 显示更多 |
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