代码

#include <iostream>
using namespace std;
typedef long long ll;

inline ll mul(ll a,ll b);
int main(void){
    ll a,b,res;
    a=1ll<<30;
    b=1ll<<29;
    a+=12313234;
    b+=76843625;
    for (int i=1;i<=10000000;i++){
        ll c=mul(a,b);
        res+=c;
    }
    cout << res << endl;
    return 0;
}

ll mul(ll a,ll b){
    ll ans=0;
    while (b){
        (b&1)?(ans+=a):(0);
        b>>=1,a<<=1;
    }
    return ans;
}

评测结果