提交记录 13371


用户 题目 状态 得分 用时 内存 语言 代码长度
S1rius 1002i. 【模板题】多项式乘法 Accepted 100 29.888 ms 9660 KB C++ 5.56 KB
提交时间 评测时间
2020-08-01 14:46:59 2020-08-01 14:47:04
#include<bits/stdc++.h>
using namespace std;
int const N=(1<<21)+5;
namespace input
{
    const int InputBufferSize=(1<<23)+5;
    char buffer[InputBufferSize],*s,*eof;
    inline void init()
    {
        assert(stdin!=NULL);
        s=buffer;
        eof=s+fread(buffer,1,InputBufferSize,stdin);
    }
    inline bool read(int &x)
    {
        x=0;
        int flag=1;
        while(!isdigit(*s)&&*s!='-')s++;
        if(eof<=s)return false;
        if(*s=='-')flag=-1,s++;
        while(isdigit(*s))x=x*10+*s++-'0';
        x*=flag;
        return true;
    }
    inline bool read(char* str)
    {
        *str=0;
        while(isspace(*s))s++;
        if(eof<s)return false;
        while(!isspace(*s))*str=0,*str=*s,str++,s++;
        *str=0;
        return true;
    }
}
namespace output
{
    const int OutputBufferSize=(1<<23)+5;
    char buffer[OutputBufferSize];
    char *s=buffer;
    inline void flush()
    {
        assert(stdout!=NULL);
        fwrite(buffer,1,s-buffer,stdout);
        s=buffer;
        fflush(stdout);
    }
    inline void print(const char ch)
    {
        if(s-buffer>OutputBufferSize-2)flush();
        *s++=ch;
    }
    inline void print(char* str)
    {
        while(*str!=0)print(char(*str++));
    }
    inline void print(int x)
    {
        char buf[25]= {0},*p=buf;
        if(x<0)print('-'),x=-x;
        if(x==0)print('0');
        while(x)*(++p)=x%10,x/=10;
        while(p!=buf)print(char(*(p--)+'0'));
    }
}
using namespace input;
using namespace output;
namespace polynomials
{
    int const p=998244353,g=3;
    int w[N],iv[N],r[N],last;
    typedef vector<int> vec;
    inline int mod(int x){return x>=p?x-p:x;}
    int pw(int x,int y)
    {
        int res=1;
        while(y)
        {
            if(y&1)res=1ll*res*x%p;
            x=1ll*x*x%p;
            y>>=1;
        }
        return res;
    }
    void init(int n)
    {
        int lim=1;
        while((lim<<1)<n)lim<<=1;
        iv[1]=1;
        for(int i=2;i<=lim;i++)iv[i]=p-1ll*p/i*iv[p%i]%p;
        for(int i=1;i<=lim;i<<=1)
        {
            int wn=pw(g,(p-1)/(i<<1)),j=0,ww=1;
            for(j=0,ww=1;j+7<i;j+=8)
            {
                w[i+j]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+1]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+2]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+3]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+4]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+5]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+6]=ww;
                ww=1ll*ww*wn%p;
                w[i+j+7]=ww;
                ww=1ll*ww*wn%p;
            }
            for(;j<i;j++)w[i+j]=ww,ww=1ll*ww*wn%p;
        }
    }
    void ntt(vec &f,int n,int op)
    {
        if(last!=n)
        {
            for(int i=1;i<n;i++)r[i]=(r[i>>1]>>1)|((i&1)?(n>>1):0);
            last=n;
        }
        for(int i=1;i<n;i++)if(i<r[i])swap(f[i],f[r[i]]);
        for(int i=1;i<n;i<<=1)
            for(int j=0,k=0,x,y;j<n;j+=i<<1)
            {
                for(k=0;k+7<i;k+=8)
                {
                    x=f[j+k],y=1ll*f[i+j+k]*w[i+k]%p;
                    f[j+k]=mod(x+y);f[i+j+k]=mod(x-y+p);
                    x=f[j+k+1],y=1ll*f[i+j+k+1]*w[i+k+1]%p;
                    f[j+k+1]=mod(x+y);f[i+j+k+1]=mod(x-y+p);
                    x=f[j+k+2],y=1ll*f[i+j+k+2]*w[i+k+2]%p;
                    f[j+k+2]=mod(x+y);f[i+j+k+2]=mod(x-y+p);
                    x=f[j+k+3],y=1ll*f[i+j+k+3]*w[i+k+3]%p;
                    f[j+k+3]=mod(x+y);f[i+j+k+3]=mod(x-y+p);
                    x=f[j+k+4],y=1ll*f[i+j+k+4]*w[i+k+4]%p;
                    f[j+k+4]=mod(x+y);f[i+j+k+4]=mod(x-y+p);
                    x=f[j+k+5],y=1ll*f[i+j+k+5]*w[i+k+5]%p;
                    f[j+k+5]=mod(x+y);f[i+j+k+5]=mod(x-y+p);
                    x=f[j+k+6],y=1ll*f[i+j+k+6]*w[i+k+6]%p;
                    f[j+k+6]=mod(x+y);f[i+j+k+6]=mod(x-y+p);
                    x=f[j+k+7],y=1ll*f[i+j+k+7]*w[i+k+7]%p;
                    f[j+k+7]=mod(x+y);f[i+j+k+7]=mod(x-y+p);
                }
                for(;k<i;k++)
                {
                    x=f[j+k],y=1ll*f[i+j+k]*w[i+k]%p;
                    f[j+k]=mod(x+y);f[i+j+k]=mod(x-y+p);
                }
            }
        if(op==-1)
        {
            reverse(&f[1],&f[n]);
            int i=0;
            for(i=0;i+7<n;i+=8)
            {
                f[i]=1ll*f[i]*iv[n]%p;
                f[i+1]=1ll*f[i+1]*iv[n]%p;
                f[i+2]=1ll*f[i+2]*iv[n]%p;
                f[i+3]=1ll*f[i+3]*iv[n]%p;
                f[i+4]=1ll*f[i+4]*iv[n]%p;
                f[i+5]=1ll*f[i+5]*iv[n]%p;
                f[i+6]=1ll*f[i+6]*iv[n]%p;
                f[i+7]=1ll*f[i+7]*iv[n]%p;
            }
            for(;i<n;i++)
                f[i]=1ll*f[i]*iv[n]%p;
        }
    }
}
using namespace polynomials;
vec a,b;
int main()
{
    //freopen("poly.in","r",stdin);
    //freopen("poly.out","w",stdout);
    input::init();
    int n,m;
    read(n),read(m);
    n++,m++;
    int lim=1;
    while(lim<(n+m-1))lim<<=1;
    init(lim+5);
    a.resize(lim),b.resize(lim);
    for(int i=0;i<n;i++)read(a[i]);
    for(int i=0;i<m;i++)read(b[i]);
    ntt(a,lim,1),ntt(b,lim,1);
    int i=0;
    for(i=0;i+7<lim;i+=8)
    {
        a[i]=1ll*a[i]*b[i]%p;
        a[i+1]=1ll*a[i+1]*b[i+1]%p;
        a[i+2]=1ll*a[i+2]*b[i+2]%p;
        a[i+3]=1ll*a[i+3]*b[i+3]%p;
        a[i+4]=1ll*a[i+4]*b[i+4]%p;
        a[i+5]=1ll*a[i+5]*b[i+5]%p;
        a[i+6]=1ll*a[i+6]*b[i+6]%p;
        a[i+7]=1ll*a[i+7]*b[i+7]%p;
    }
    for(;i<lim;i++)a[i]=1ll*a[i]*b[i]%p;
    ntt(a,lim,-1);
    for(int i=0;i<n+m-1;i++)print(a[i]),print(' ');
    flush();
    return 0;
}

CompilationN/AN/ACompile OKScore: N/A

Subtask #1 Testcase #137.24 us56 KBAcceptedScore: 0

Subtask #1 Testcase #229.731 ms9 MB + 284 KBAcceptedScore: 0

Subtask #1 Testcase #313.056 ms3 MB + 812 KBAcceptedScore: 100

Subtask #1 Testcase #413.124 ms3 MB + 792 KBAcceptedScore: 0

Subtask #1 Testcase #539.24 us56 KBAcceptedScore: 0

Subtask #1 Testcase #637.43 us56 KBAcceptedScore: 0

Subtask #1 Testcase #736.51 us56 KBAcceptedScore: 0

Subtask #1 Testcase #828.89 ms8 MB + 700 KBAcceptedScore: 0

Subtask #1 Testcase #928.899 ms8 MB + 700 KBAcceptedScore: 0

Subtask #1 Testcase #1028.101 ms8 MB + 96 KBAcceptedScore: 0

Subtask #1 Testcase #1129.888 ms9 MB + 444 KBAcceptedScore: 0

Subtask #1 Testcase #1226.748 ms7 MB + 204 KBAcceptedScore: 0

Subtask #1 Testcase #1336.99 us56 KBAcceptedScore: 0


Judge Duck Online | 评测鸭在线
Server Time: 2024-05-04 01:24:34 | Loaded in 1 ms | Server Status
个人娱乐项目,仅供学习交流使用