提交记录 13639


用户 题目 状态 得分 用时 内存 语言 代码长度
fjzzq2002 mmmd1k. 测测你的双精度矩阵乘法-1k Wrong Answer 0 383.188 ms 8232 KB C++ 1.11 KB
提交时间 评测时间
2020-08-05 20:19:35 2020-08-05 20:19:37
#define BLOCK_SIZE_L1 32
#define BLOCK_SIZE_L2 64
#define BLOCK_SIZE_L3 128
#define MIN(a,b) ((a)<(b)?(a):(b))
#pragma GCC optimize("-Ofast","-funroll-all-loops","-ffast-math","-ftree-vectorize")
__attribute__((optimize("tree-vectorize"))) void matrix_multiply(int n_,const double* B,const double* A,double* C)
{
	const int n=1024;
	__attribute__((aligned(64))) double c[BLOCK_SIZE_L1][BLOCK_SIZE_L3];
	for(int ii=0;ii<n;ii+=BLOCK_SIZE_L3)
		for(int kk=0;kk<n;kk+=BLOCK_SIZE_L1)
		{
			#define ui BLOCK_SIZE_L3
			#define uj BLOCK_SIZE_L2
			#define uk BLOCK_SIZE_L1
			for(int k=0;k<uk;++k)
				for(int i=0;i<ui;++i) c[k][i]=0;
			for(int jj=0;jj<n;jj+=BLOCK_SIZE_L2)
			{
				const double*__restrict__ bb=B+jj+kk*n;
				const double*__restrict__ aa=A+ii+jj*n;
				bb=(const double*)((long long)bb&(~4095));
				aa=(const double*)((long long)aa&(~4095));
				for(int k=0;k<uk;++k)
					for(int j=0;j<uj;j++)
						for(int i=0;i<ui;i++)
							c[k][i]+=aa[i+j*n]*bb[j+k*n];
			}
			double*__restrict__ cc=C+ii+kk*n;
			cc=(double*)((long long)cc&(~4095));
			for(int k=0;k<uk;++k)
				for(int i=0;i<ui;++i)
					cc[i+k*n]+=c[k][i];
		}
}

CompilationN/AN/ACompile OKScore: N/A

Testcase #1383.188 ms8 MB + 40 KBWrong AnswerScore: 0


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