代码

#include <random>
#include <chrono>

std::mt19937 rng(std::chrono::steady_clock::now().time_since_epoch().count());

const int N = 1000;

int A[N][N], B[N][N], C[N][N];

int main() {
	for (int i = 0; i < N; ++i) {
		for (int j = 0; j < N; ++j) {
			A[i][j] = rng() & 0x3fffffff;
			B[i][j] = rng() & 0x3fffffff;
			C[i][j] = 0;
		}
	}
	return 0;
}

评测结果