提交记录 15156


用户 题目 状态 得分 用时 内存 语言 代码长度
bs2016010 1002i. 【模板题】多项式乘法 Time Limit Exceeded 0 1 s 234416 KB C++ 1.93 KB
提交时间 评测时间
2020-12-02 21:59:38 2020-12-02 21:59:49
#include<bits/stdc++.h>
#define ll long long
#define ld long double
#define ull unsigned ll
#define db double
#define pint pair<int,int>
#define mk make_pair
#define pb push_back
#define eb emplace_back
#define ins insert
#define fi first
#define se second
#define Rep(x,y,z) for(int x=y;x<=z;x++)
#define Red(x,y,z) for(int x=y;x>=z;x--)
using namespace std;
const int Mod=998244353,MAXN=3e7+5;
char buf[1<<12],*pp1=buf,*pp2=buf,nc;int ny;
inline char gc() {return pp1==pp2&&(pp2=(pp1=buf)+fread(buf,1,1<<12,stdin),pp1==pp2)?EOF:*pp1++;}
//inline char gc(){return getchar();}
inline int read(){
	int x=0;for(ny=1;nc=gc(),(nc<48||nc>57)&&nc!=EOF;)if(nc==45)ny=-1;if(nc<0)return nc;
	for(x=nc-48;nc=gc(),47<nc&&nc<58&&nc!=EOF;x=(x<<3)+(x<<1)+(nc^48));return x*ny;
}
int n,m,r,Fac[MAXN],iFac[MAXN],*F1;
inline int M(int x){return (x>=Mod)?(x-Mod):x;}
inline int Fp(int x,int k){int ans=1;for(;k;k>>=1,x=1ll*x*x%Mod)if(k&1)ans=1ll*ans*x%Mod;return ans;}
inline void Init(int n=3e7){
	Fac[0]=1;Rep(i,1,n)Fac[i]=1ll*Fac[i-1]*i%Mod;
	iFac[n]=Fp(Fac[n],Mod-2);Red(i,n,1)iFac[i-1]=1ll*iFac[i]*i%Mod;
}
inline int C(int n,int m){return n<0||m<0||n<m?0:1ll*Fac[n]*iFac[m]%Mod*iFac[n-m]%Mod;}
int main(){
//	freopen("std.in","r",stdin);
//	freopen("std.out","w",stdout);
	//n=read(),m=read(),r=read();
	n=1.5e7;m=1.5e7;F1=Fac+n-1;
	Init();int ans=0;
	cerr<<clock()<<endl;
	for(int i=0;i<=m;i++)F1[i]=1ll*F1[i]*iFac[i]%Mod;
	for(int i=1;i<=n;i++)
	{
		int res=0;
		for(int *p1=F1+m-i,j=i;j<=m;p1-=i,j+=i)res=M(res+*p1);ans^=res;
	}
	cerr<<ans;
/*	int ans=0;
	Rep(i,r+1,n){
		int t1=0,t2=0;
		Rep(j,1,m)if(i*j<=m)t1=(t1+C(m-i*j+n-1,n-1))%Mod;else break;
		Rep(k,1,r)t2=(t2+1ll*(i-k&1?Mod-1:1)*C(i-1,k-1))%Mod;
		ans=(ans+1ll*t1*t2%Mod*C(n,i))%Mod;
	}
	int i=1;
	int t1=0,t2=0;
	Rep(j,1,m)t1=(t1+C(m-i*j+n-1,n-1))%Mod;
	Rep(k,1,min(r,i))t2=(t2+1ll*(i-k&1?Mod-1:1)*C(i-1,k-1))%Mod;
	ans=(ans+1ll*t1*t2%Mod*C(n,i))%Mod;
	cout<<(1ll*ans*Fp(C(n+m-1,n-1),Mod-2)%Mod+r)%Mod<<"\n";
	return 0;*/
}




CompilationN/AN/ACompile OKScore: N/A

Subtask #1 Testcase #11 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #21 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #31 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #41 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #51 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #61 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #71 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #81 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #91 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #101 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #111 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #121 s228 MB + 944 KBTime Limit ExceededScore: 0

Subtask #1 Testcase #131 s228 MB + 944 KBTime Limit ExceededScore: 0


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