提交记录 16085


用户 题目 状态 得分 用时 内存 语言 代码长度
cyf 1002i. 【模板题】多项式乘法 Wrong Answer 0 26.002 ms 15396 KB C++11 5.23 KB
提交时间 评测时间
2021-03-24 14:25:00 2021-03-24 14:25:05
#include <bits/stdc++.h>
#define maxn 500005
#define mod 998244353
#define LL long long
using namespace std;
void Inc(int &x,int y) { x+=y; (x>=mod)&&(x-=mod); }
int add(int x,int y) { x+=y; (x>=mod)&&(x-=mod); return x; }
void Dec(int &x,int y) { x-=y; (x<0)&&(x+=mod); }
int sub(int x,int y) { x-=y; (x<0)&&(x+=mod); return x;}
int mul(int x,int y) { return 1ll*x*y%mod; }
namespace Math {
	LL w;
	struct N{ LL a,b; };
	N operator * (const N &x,const N &y){ return (N){(x.a*y.a%mod+w*x.b%mod*y.b%mod)%mod,(x.a*y.b%mod+y.a*x.b%mod)%mod}; }
	inline LL power(N n,LL x) { N res=(N){1,0}; for(;x;n=n*n,x>>=1) if(x&1) res=res*n; return res.a; }
	inline bool check(LL x){return power((N){x,0},(mod-1)>>1)==1;}
	inline int work(LL n){
		srand((unsigned)time(NULL));
		if(n==0) return 0; LL a=rand()%mod; while(!a||check((a*a+mod-n)%mod)) a=rand()%mod;
		w=(a*a+mod-n)%mod; int ans=power((N){a,1},(mod+1)>>1); return min(ans,mod-ans);
	}
}
#define inv2 499122177
int Wl,Wl2,w[maxn],lg[maxn],inv[maxn];
inline int Pow(int b, int k) { int r=1; for(;k;k>>=1,b=1ll*b*b%mod) if(k&1) r=1ll*r*b%mod; return r; }
inline void init(int n) {
	for(Wl=1;n>=Wl<<1;Wl<<=1) ; int pw=Pow(3,(mod-1)/(Wl2=Wl<<1)); w[Wl]=inv[0]=inv[1]=1;
	for(int i=Wl+1;i<=Wl2;i++) w[i]=w[i-1]*1ll*pw%mod; for(int i=Wl-1;i>=1;i--) w[i]=w[i<<1];
	for(int i=2;i<=Wl2;i++) inv[i]=1ll*(mod-mod/i)*inv[mod%i]%mod,lg[i]=lg[i>>1]+1;
}
inline int upd(int x) { return x+=x>>31&mod; }
inline void NTT(int *A, int n, int tp) {
	static int r[maxn]={}; static unsigned LL ar[maxn]={}; if(tp^1) reverse(A+1,A+n);
	for(int i=0;i<n;i++) r[i]=(r[i>>1]>>1|(i&1)<<lg[n]-1),ar[i]=upd(A[r[i]]);
	for(int L=1;L<n;L<<=1) for(int s=0,L2=L<<1;s<n;s+=L2)
	for(int k=s,x=L,t;x<L2;x++,k++) t=ar[k+L]*w[x]%mod,ar[k+L]=ar[k]-t+mod,ar[k]+=t;
	for(int i=0;i<n;i++) A[i]=ar[i]%mod;
	if(tp^1) for(int i=0;i<n;i++) A[i]=1ll*A[i]*inv[n]%mod;
}
#define Poly vector<int>
#define Rev(A) reverse(A.begin(),A.end())
inline Poly Add(Poly A,Poly B) {
	if(A.size()<B.size()) A.resize(B.size()); else if(A.size()>B.size()) B.resize(A.size());
	Poly C; C.resize(A.size()); for(int i=0;i<(int)A.size();i++) C[i]=add(A[i],B[i]); return C;
}
inline Poly Sub(Poly A,Poly B) { for(int i=0;i<(int)B.size();i++) B[i]=(B[i]==0)?0:(mod-B[i]); return Add(A,B); }
inline Poly Der(Poly A) { int n=A.size(); for(int i=1;i<n;i++) A[i-1]=1ll*i*A[i]%mod; A[n-1]=0; return A; }
inline Poly Int(Poly A) { int n=A.size(); for(int i=n-1;i>0;i--) A[i]=1ll*A[i-1]*inv[i]%mod; A[0]=0; return A; }
inline Poly Mul(Poly A,Poly B,int l=-1) {
	int n=A.size(),m=B.size(),N=n+m-1,M=1<<lg[N]+1;
	A.resize(M); B.resize(M); NTT(A.data(),M,1); NTT(B.data(),M,1);
	for(int i=0;i<M;i++) A[i]=1ll*A[i]*B[i]%mod;
	NTT(A.data(),M,-1); if(~l) A.resize(l); else A.resize(N); return A;
}
inline Poly Mul(Poly A,int B) { for(int i=0;i<(int)A.size();i++) A[i]=1ll*A[i]*B%mod; return A; }
inline Poly Inv(Poly A,int n=-1) {
	static int t[maxn],tt[maxn]; if(~n) n=A.size();
	A.resize(n<<1); Poly B(n<<1); B[0]=Pow(A[0],mod-2);
	for (int k=2;k<(n<<1);k<<=1) {
		memcpy(t,A.data(),k<<2); memcpy(tt,B.data(),k<<2);
		NTT(t,k,1),NTT(B.data(),k,1);  for(int i=0;i<k;i++) t[i]=1ll*t[i]*B[i]%mod; NTT(t,k,-1);
		fill(t,t+(k>>1),0); NTT(t,k,1); for(int i=0;i<k;i++) B[i]=1ll*B[i]*t[i]%mod; NTT(B.data(),k,-1);
		fill(B.data(),B.data()+(k>>1),0); for(int i=0;i<k;i++) B[i]=upd(tt[i]-B[i]);
	} B.resize(n); return B;
}
inline Poly div(Poly A,Poly B) {
	int len=2; while(len<A.size()) len<<=1;
	Poly C=Inv(A,len>>1);
}
inline Poly Ln(Poly A) { return Int(Mul(Der(A),Inv(A),A.size())); }
inline Poly Exp(Poly A) {
	int n=A.size(); A.resize(n<<1); Poly B(1),C; B[0]=1;
	for(int k=2;k<(n<<1);k<<=1,B=Mul(B,C,k)) {
		C=Ln(B); C.resize(k);
		for(int i=0;i<k;i++) C[i]=((i==0)+A[i]-C[i])%mod;
	} B.resize(n); return B;
}
inline Poly Sqrt(Poly A) {
	int n=A.size();A.resize(n<<2);
	Poly B,C; B.push_back(Math::work(A[0]));
	for(int l=2;l<(n<<1);l<<=1) {
		B.resize(l); C.resize(l); for(int i=0;i<l;i++) C[i]=A[i];
		B=Mul(Add(B,Mul(C,Inv(B),l)),inv2);
	} B.resize(n); if((B[0]<<1)>mod) for(int i=0;i<n;i++) B[i]=(B[i]==0)?0:(mod-B[i]);
	return B;
}
inline Poly _pow(Poly A,int k) {
	int x=A[0],n=A.size(); for(int i=0,iv=Pow(x,mod-2);i<n;i++) A[i]=1ll*A[i]*iv%mod;
	A=Ln(A); for(int i=0;i<n;i++) A[i]=1ll*A[i]*k%mod;
	A=Exp(A); for(int i=0,iv=Pow(x,k);i<n;i++)A[i]=1ll*A[i]*iv%mod;
	return A;
}
inline int Init(int n) { int m; for(m=1;m<=n;m<<=1); init(m); return m; }
int n,m; Poly A,B;
namespace IO {
	inline char nc(){
		static char buf[500005],*p1=buf,*p2=buf;
		return p1==p2&&(p2=(p1=buf)+fread(buf,1,500000,stdin),p1==p2)?EOF:*p1++;
	}
	char out[500005],*pout=out,*eout=out+500000;
	inline void flush() { fwrite(out,1,pout-out,stdout),pout=out; }
	inline void pc(char c) { pout==eout&&(fwrite(out,1,500000,stdout),pout=out); (*pout++)=c; }
	template<typename T> inline void put(T x,char suf) {
		static char stk[40];int top=0; while(x) stk[top++]=x%10,x/=10;
		!top?pc('0'),0:0; while(top--) pc(stk[top]+'0'); pc(suf);
	}
	inline int read(){
		char ch=nc(); int sum=0; for(;ch<'0'||ch>'9';ch=nc());
		while(ch>='0'&&ch<='9')sum=(sum<<1)+(sum<<3)+ch-48,ch=nc();
		return sum;
	}
}
#define Rint IO::read()
using IO::put;
int main(){
	A.resize(n=Rint+1); B.resize(m=Rint+1);
	for(int i=0;i<n;i++) A[i]=Rint; for(int i=0;i<m;i++) B[i]=Rint;
	Init(n+m+233); A=Mul(A,B); for(int x:A) put(x,' '); IO::flush();
}

CompilationN/AN/ACompile OKScore: N/A

Subtask #1 Testcase #143.07 us68 KBAcceptedScore: 0

Subtask #1 Testcase #225.977 ms15 MB + 36 KBWrong AnswerScore: 0

Subtask #1 Testcase #310.033 ms7 MB + 72 KBAcceptedScore: 0

Subtask #1 Testcase #410.069 ms7 MB + 52 KBAcceptedScore: 0

Subtask #1 Testcase #544.6 us68 KBAcceptedScore: 0

Subtask #1 Testcase #642.62 us68 KBAcceptedScore: 0

Subtask #1 Testcase #743.79 us68 KBAcceptedScore: 0

Subtask #1 Testcase #825.101 ms14 MB + 396 KBWrong AnswerScore: 0

Subtask #1 Testcase #925.118 ms14 MB + 396 KBWrong AnswerScore: 0

Subtask #1 Testcase #1024.157 ms13 MB + 748 KBWrong AnswerScore: 0

Subtask #1 Testcase #1126.002 ms15 MB + 36 KBWrong AnswerScore: 0

Subtask #1 Testcase #1221.849 ms13 MB + 448 KBAcceptedScore: 0

Subtask #1 Testcase #1343.2 us68 KBAcceptedScore: 0


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