#include <cstdio>
#include <cctype>
#include <algorithm>
#include <cmath>
namespace fastIO {
const int SZ = 1 << 25;
char ibuf[SZ], *p0 = ibuf, *p1 = ibuf;
inline char getchar(void) { return p0 == p1 && (p1 = (p0 = ibuf) + fread(ibuf, 1, SZ, stdin), p0 == p1) ? EOF : *p0++; }
char char_read; void read(auto &val) {
val = 0; do char_read = getchar(); while(!isdigit(char_read));
do val = val * 10 + char_read - '0'; while(isdigit(char_read = getchar()));
}
char obuf[SZ], *p = obuf;
inline void putchar(char char_write) { *p++ = char_write; }
void write(auto val) { if(val >= 10) write(val / 10); putchar(val % 10 + '0'); }
inline void write(auto a[], int sz) { for(int i = 0; i < sz; ++i) write(a[i]), putchar(' '); putchar('\n'); }
void output(void) { fwrite(obuf, p - obuf, 1, stdout);}
};
const int N = 1 << 21;
const float PI = acos(-1);
struct CMPLX {
float a, b; // a + bi
CMPLX operator + (CMPLX z) const { return (CMPLX){ a + z.a, b + z.b}; }
CMPLX operator - (CMPLX z) const { return (CMPLX){ a - z.a, b - z.b}; }
CMPLX operator * (CMPLX z) const { return (CMPLX){ a * z.a - b * z.b, a * z.b + b * z.a}; }
} c[N];
CMPLX w[N + 1];
CMPLX fft_sup[N];
inline void fft(auto a[], int n) {
auto b = fft_sup, j = a, _j = a; int i, k, _k; auto _w = w;
for(i = 1; i < n; i <<= 1, std :: swap(a, b))
for(k = 0, j = a, _j = a + (n >> 1), _w = w; k != n; k += i, _w += i)
for(_k = k, k += i; _k != k; ++j, ++_j, ++_k)
b[_k] = *j + *_j,
b[_k + i] = (*j - *_j) * *_w;
if(b != fft_sup) std :: copy(a, a + n, b);
}
inline void ifft(auto a[], int n) {
auto b = fft_sup, j = a, _j = a; int i, k, _k; auto _w = w;
for(i = 1; i < n; i <<= 1, std :: swap(a, b))
for(k = 0, j = a, _j = a + (n >> 1), _w = w + n; k != n; k += i, _w -= i)
for(_k = k, k += i; _k != k; ++j, ++_j, ++_k)
b[_k] = *j + *_j,
b[_k + i] = (*j - *_j) * *_w;
if(b != fft_sup) std :: copy(a, a + n, b);
}
inline void poly_mul(auto a[], auto b[], int n) {
CMPLX _w = (CMPLX){ cos(PI / n * 2), sin(PI / n * 2)};
w[0].a = 1; for(int i = 1; i <= n; ++i) w[i] = w[i - 1] * _w;
for(int i = 0; i < n; ++i) c[i].a = a[i], c[i].b = b[i]; fft(c, n);
for(int i = 0; i < n; ++i) c[i] = c[i] * c[i]; ifft(c, n);
float _n = 0.5 / n; for(int i = 0; i < n; ++i) a[i] = c[i].b * _n + 0.123;
}
int n, n_a, n_b;
int a[N], b[N];
int main(void) {
fastIO :: read(n_a), fastIO :: read(n_b); for(n = 1; n <= n_a + n_b; n <<= 1);
for(int i = 0; i <= n_a; ++i) fastIO :: read(a[i]);
for(int i = 0; i <= n_b; ++i) fastIO :: read(b[i]);
poly_mul(a, b, n);
fastIO :: write(a, n_a + n_b + 1), fastIO :: output();
return 0;
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Subtask #1 Testcase #1 | 9.14 us | 40 KB | Accepted | Score: 0 | 显示更多 |
| Subtask #1 Testcase #2 | 18.111 ms | 10 MB + 648 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #3 | 7.659 ms | 4 MB + 664 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #4 | 7.597 ms | 4 MB + 196 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #5 | 9.27 us | 40 KB | Accepted | Score: 0 | 显示更多 |
| Subtask #1 Testcase #6 | 9.2 us | 40 KB | Accepted | Score: 0 | 显示更多 |
| Subtask #1 Testcase #7 | 9.22 us | 40 KB | Accepted | Score: 0 | 显示更多 |
| Subtask #1 Testcase #8 | 17.267 ms | 10 MB + 48 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #9 | 17.257 ms | 9 MB + 940 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #10 | 16.438 ms | 9 MB + 336 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #11 | 18.339 ms | 10 MB + 812 KB | Wrong Answer | Score: 0 | 显示更多 |
| Subtask #1 Testcase #12 | 15.114 ms | 8 MB + 568 KB | Accepted | Score: 0 | 显示更多 |
| Subtask #1 Testcase #13 | 8.73 us | 40 KB | Accepted | Score: 0 | 显示更多 |