代码

#define idx(i, j) ((i) * n + (j))

double fu;
void matrix_multiply(int n, const double *A, const double *B, double *C) {
	for (int i = 0; i < n; i++) {
		for (int k = 0; k < n; k++) {
			fu = A[idx(i,k)];	
			for (int j = 0; j < n; j++) {
				C[idx(i, j)] += fu * B[idx(k, j)];
			}
		}
	}
}

评测结果