提交记录 17803
| 提交时间 |
评测时间 |
| 2022-07-16 21:39:55 |
2023-09-03 19:42:14 |
#include <bits/stdc++.h>
using namespace std;
int n;
int a[100001];
int t[100001];
// C++ Version
void merge(int ll, int rr) {
// 用来把 a 数组 [ll, rr - 1] 这一区间的数排序。 t
// 数组是临时存放有序的版本用的。
if (rr - ll <= 1) return;
int mid = ll + ((rr - ll) >> 1);
merge(ll, mid);
merge(mid, rr);
int p = ll, q = mid, s = ll;
while (s < rr) {
if (p >= mid || (q < rr && a[p] > a[q])) {
t[s++] = a[q++];
// ans += mid - p;
} else
t[s++] = a[p++];
}
for (int i = ll; i < rr; ++i) a[i] = t[i];
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
n = 5;
a[1] = 4;
a[2] = 3;
a[3] = 2;
a[4] = 5;
a[5] = 1;
merge(1, n);
for (int i = 1; i <= n; ++i) {
cout << a[i] << ' ' ;
}
cout << endl;
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 46.46 us | 68 KB | Accepted | Score: 100 | 显示更多 |
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