代码

// 19090
void count_5d(int n, const unsigned *x[5], unsigned *out) {
	for (int i=0; i<n; ++i) for (int j=0; j<n; ++j) {
#define o(k) x[k][i]<x[k][j]
out[j] += o(0) & o(1) & o(2) & o(3) & o(4);
}
}

评测结果