提交记录 19195
| 提交时间 |
评测时间 |
| 2023-02-24 16:54:29 |
2023-09-03 19:42:27 |
#include <stdio.h>
#include <string.h>
int F[114514];
long long fib(int n){
if(F[n]!=-1) return F[n];
else return F[n]=fib(n-1)+fib(n-2);
}
int main() {
memset(F,-1,sizeof(F));
F[0]=0,F[1]=0,F[2]=1;
printf("%lld %lld %lld\n",fib(233),fib(114514),fib(1919810));
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 45.45 us | 464 KB | Accepted | Score: 100 | 显示更多 |
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