提交记录 19197
提交时间 |
评测时间 |
2023-02-24 16:56:57 |
2023-09-03 19:42:27 |
#include <stdio.h>
#include <string.h>
long long F[233];
long long fib(int n) {
if (F[n] != -1)
return F[n];
else
return F[n] = fib(n - 1) + fib(n - 2);
}
int main() {
memset(F, -1, sizeof(F));
F[0] = 0, F[1] = 0, F[2] = 1;
printf("%lld %lld %lld\n", fib(20), fib(40), fib(80));
}
Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
Testcase #1 | 8.38 us | 12 KB | Accepted | Score: 100 | 显示更多 |
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