代码

void count_5d(int n, const unsigned *x[5], unsigned *out) {
	// Your code here
for(int i=1;i<=n;i++)
{
out[i]=0;
for(int j=1;j<=n;j++)
{
int o=1;
for(int k=0;k<5;k++)o&=x[k][j]<x[k][i];
out[i]+=o;
}
}
}

评测结果