代码

void count_5d(int n, const unsigned *x[5], unsigned *out) {
	// Your code here
for(int i=1;i<=n;i++)
{
out[i]=0;
for(int j=1;j<=n;j++)
out[i]+=x[0][j]<x[0][i]&&x[1][j]<x[1][i]&&x[2][j]<x[2][i]&&x[3][j]<x[3][i]&&x[4][j]<x[4][i];
}
}

评测结果