#include <stdint.h>
#include <stdlib.h>
typedef unsigned long u64;
static u64 *b1[3], *b2[3];
static inline int popc(u64 x){
x = x - ((x >> 1) & 0x5555555555555555ULL);
x = (x & 0x3333333333333333ULL) + ((x >> 2) & 0x3333333333333333ULL);
x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0fULL;
return (int)((x * 0x0101010101010101ULL) >> 56);
}
static unsigned count_query(int x, int y, int l){
long long d = (long long)y - x;
int off = (int)(d & 63);
int woff = (int)(d >> 6);
unsigned ans = 0;
int w_start = x >> 6, boff = x & 63;
int end = x + l;
int w_end = (end - 1) >> 6, beoff = (end - 1) & 63;
u64 *A0=b1[0], *A1=b1[1], *A2=b1[2];
u64 *B0=b2[0], *B1=b2[1], *B2=b2[2];
for(int w=w_start; w<=w_end; w++){
int wb = w + woff;
u64 a0=A0[w], a1=A1[w], a2=A2[w];
u64 sb0,sb1,sb2;
if(off){ sb0=(B0[wb+1]<<(64-off))|(B0[wb]>>off); sb1=(B1[wb+1]<<(64-off))|(B1[wb]>>off); sb2=(B2[wb+1]<<(64-off))|(B2[wb]>>off); }
else { sb0=B0[wb]; sb1=B1[wb]; sb2=B2[wb]; }
u64 win=(a0&sb1)|(a1&sb2)|(a2&sb0);
if(w==w_start) win &= (~0ULL)<<boff;
if(w==w_end && beoff!=63) win &= ((1ULL<<(beoff+1))-1);
ans += popc(win);
}
return ans;
}
void solve(int n, int q, char *s1, char *s2, int *q_x, int *q_y, int *q_len, unsigned *ans){
// map distinct bytes (sorted) to 0,1,2
static unsigned char mp[256];
for(int i=0;i<256;i++) mp[i]=0;
int vals[3], nv=0;
unsigned char seen[256];
for(int i=0;i<256;i++) seen[i]=0;
for(int i=0;i<n;i++){ unsigned char c=(unsigned char)s1[i]; if(!seen[c]){ seen[c]=1; if(nv<3) vals[nv++]=c; } }
for(int i=0;i<n;i++){ unsigned char c=(unsigned char)s2[i]; if(!seen[c]){ seen[c]=1; if(nv<3) vals[nv++]=c; } }
for(int a=0;a<nv-1;a++) for(int b=a+1;b<nv;b++) if(vals[b]<vals[a]){ int t=vals[a];vals[a]=vals[b];vals[b]=t; }
for(int k=0;k<nv && k<3;k++) mp[vals[k]]=k;
int NW = (n+63)/64 + 4;
for(int a=0;a<3;a++){ b1[a]=calloc(NW,8); b2[a]=calloc(NW,8); }
b1[0]+=2;b1[1]+=2;b1[2]+=2;b2[0]+=2;b2[1]+=2;b2[2]+=2;
for(int i=0;i<n;i++){
int a=mp[(unsigned char)s1[i]];
int b=mp[(unsigned char)s2[i]];
b1[a][i>>6]|=1ULL<<(i&63);
b2[b][i>>6]|=1ULL<<(i&63);
}
for(int qi=0; qi<q; qi++) ans[qi] = count_query(q_x[qi], q_y[qi], q_len[qi]);
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 176.19 us | 44 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #2 | 2.182 s | 5 MB + 400 KB | Wrong Answer | Score: 0 | 显示更多 |