// NOI2017 分身术 - convex layers + materialize exposed chain + Graham scan (correctness-first).
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
static const int MAXN = 100005;
static ll X[MAXN], Y[MAXN];
static inline ll crs3(int a,int b,int c){ return (X[b]-X[a])*(Y[c]-Y[b])-(Y[b]-Y[a])*(X[c]-X[b]); }
static inline ll cross2(int a,int b){ return X[a]*Y[b]-Y[a]*X[b]; }
static int K;
static vector<int> vert[130];
static int h[130];
static vector<ll> pref[130];
static int layer_of[MAXN], pos_of[MAXN];
static vector<pair<int,int>> dels;
static int n, m;
static void collectDeleted(int d, int lo, int hi, vector<int>& out){
out.clear();
int hd = h[d];
for(auto& pr : dels){
if(pr.first != d) continue;
int p = pr.second;
if(lo <= p && p <= hi) out.push_back(p);
if(lo <= p+hd && p+hd <= hi) out.push_back(p+hd);
}
sort(out.begin(), out.end());
out.erase(unique(out.begin(), out.end()), out.end());
}
// append exposed chain (surviving layer-d2 f<0 + recursive dips) between anchors A,B (excluding A,B).
// A,B are points (indices into global X/Y). d2 = layer whose f<0 we consider.
static void buildArc(int d2, int lo, int hi, int anchorL, int anchorR, vector<int>& out);
static void buildExposed(int d, int A, int B, vector<int>& out){
int d2 = d+1;
if(d2 >= K) return;
int h2 = h[d2];
int e0 = -1; bool anyNon = false;
for(int t=0;t<h2;t++){ if(crs3(A,B,vert[d2][t]) < 0){ if(e0<0)e0=t; } else anyNon = true; }
if(e0 == -1) return;
int fa, fb;
if(!anyNon){ fa = 0; fb = h2-1; }
else {
fa = e0; fb = e0;
for(int st=0; st<h2 && crs3(A,B,vert[d2][(fb+1)%h2])<0; st++) fb=(fb+1)%h2;
for(int st=0; st<h2 && crs3(A,B,vert[d2][(fa-1+h2)%h2])<0; st++) fa=(fa-1+h2)%h2;
}
int lo = fa, hi = (fb >= fa) ? fb : fb + h2;
buildArc(d2, lo, hi, A, B, out);
}
static void buildArc(int d2, int lo, int hi, int A, int B, vector<int>& out){
int h2 = h[d2];
vector<int> dp; collectDeleted(d2, lo, hi, dp);
if(dp.empty()){
for(int t=lo;t<=hi;t++) out.push_back(vert[d2][t % h2]);
return;
}
int cur = lo;
int i = 0;
while(i < (int)dp.size()){
int p = dp[i], q = p;
while(i+1 < (int)dp.size() && dp[i+1] == q+1) q = dp[++i];
for(int t=cur;t<=p-1;t++) out.push_back(vert[d2][t % h2]);
buildExposed(d2, A, B, out);
cur = q+1;
i++;
}
for(int t=cur;t<=hi;t++) out.push_back(vert[d2][t % h2]);
}
static char inbuf[1<<22]; static size_t inpos=0, inlen=0;
static inline char gc(){ if(inpos>=inlen){ inlen=fread(inbuf,1,sizeof(inbuf),stdin); inpos=0; if(inlen==0)return 0; } return inbuf[inpos++]; }
static inline ll rd(){ char c; while((c=gc()) && (c<'0'||c>'9') && c!='-'); if(c==0) return 0; int s=1; if(c=='-'){s=-1;c=gc();} ll v=0; while(c>='0'&&c<='9'){v=v*10+(c-'0');c=gc();} return s*v; }
static char outbuf[1<<22]; static size_t outpos=0;
static inline void wl(ll v){ if(outpos>(1<<22)-64){fwrite(outbuf,1,outpos,stdout);outpos=0;} if(v==0){outbuf[outpos++]='0';outbuf[outpos++]='\n';return;} char t[32];int z=0; if(v<0){outbuf[outpos++]='-';v=-v;} while(v){t[z++]='0'+(v%10);v/=10;} while(z)outbuf[outpos++]=t[--z]; outbuf[outpos++]='\n'; }
int main(){
n = (int)rd(); m = (int)rd();
for(int i=0;i<n;i++){ X[i]=rd(); Y[i]=rd(); layer_of[i]=-1; }
{
vector<char> used(n,0);
int rem = n; K = 0;
while(rem >= 3 && K < 120){
vector<int> cur;
for(int i=0;i<n;i++) if(!used[i]) cur.push_back(i);
sort(cur.begin(), cur.end(), [](int a,int b){ return X[a]!=X[b]?X[a]<X[b]:Y[a]<Y[b]; });
int sz = cur.size();
vector<int> lo;
for(int idx:cur){ while(lo.size()>=2 && crs3(lo[lo.size()-2],lo.back(),idx)<=0) lo.pop_back(); lo.push_back(idx); }
vector<int> up;
for(int t=sz-1;t>=0;t--){ int idx=cur[t]; while(up.size()>=2 && crs3(up[up.size()-2],up.back(),idx)<=0) up.pop_back(); up.push_back(idx); }
vector<int> H = lo;
for(int t=1;t<(int)up.size()-1;t++) H.push_back(up[t]);
if(H.size() < 3) break;
vert[K]=H; h[K]=H.size();
for(int t=0;t<h[K];t++){ layer_of[H[t]]=K; pos_of[H[t]]=t; used[H[t]]=1; }
K++; rem -= H.size();
}
if(rem>0){
vector<int> rest;
for(int i=0;i<n;i++) if(!used[i]) rest.push_back(i);
sort(rest.begin(), rest.end(), [](int a,int b){ return X[a]!=X[b]?X[a]<X[b]:Y[a]<Y[b]; });
vert[K]=rest; h[K]=rest.size();
for(int t=0;t<h[K];t++){ layer_of[rest[t]]=K; pos_of[rest[t]]=t; }
K++;
}
}
ll S = -1;
dels.reserve(110);
static vector<int> hull; hull.reserve(MAXN*2);
for(int q=0;q<m;q++){
int k = (int)rd();
dels.clear();
for(int j=0;j<k;j++){
ll c = rd(); ll v = S + c; v %= n; if(v<0) v += n;
int id = (int)v;
if(layer_of[id] >= 0) dels.push_back({layer_of[id], pos_of[id]});
}
// build new hull in CCW order: surviving L0 + exposed
int h0 = h[0];
vector<int> del0;
for(auto& pr : dels) if(pr.first==0) del0.push_back(pr.second);
sort(del0.begin(), del0.end());
hull.clear();
int sz = 0;
vector<int> surv;
for(int t=0;t<h0;t++) if(!binary_search(del0.begin(), del0.end(), t)) surv.push_back(t);
if(surv.size() <= 1){
// degenerate (won't happen under the >=2-surviving guarantee): brute force
for(int i=0;i<n;i++){ bool del=false; for(auto& pr : dels) if(vert[pr.first][pr.second]==i){ del=true; break; } if(!del) hull.push_back(i); }
} else {
int ssz = surv.size();
for(int t=0;t<ssz;t++){
int Xp = surv[t];
int Yp = surv[(t+1)%ssz];
hull.push_back(vert[0][Xp]);
int A = vert[0][Xp];
int B = vert[0][Yp];
buildExposed(0, A, B, hull);
}
}
// Andrew's convex hull of 'hull' (already CCW-ish but may have interior points) -> area
ll ans = 0;
if(hull.size() >= 3){
sort(hull.begin(), hull.end(), [](int a,int b){ return X[a]!=X[b]?X[a]<X[b]:Y[a]<Y[b]; });
hull.erase(unique(hull.begin(), hull.end()), hull.end());
int hs = hull.size();
if(hs >= 3){
static int stk[MAXN*2];
int top = 0;
for(int idx : hull){
while(top>=2 && crs3(stk[top-2], stk[top-1], idx)<=0) top--;
stk[top++] = idx;
}
int lower = top;
for(int t=hs-2;t>=0;t--){
int idx = hull[t];
while(top>lower && crs3(stk[top-2], stk[top-1], idx)<=0) top--;
stk[top++] = idx;
}
top--;
ll s2 = 0;
for(int i=0;i<top;i++) s2 += cross2(stk[i], stk[(i+1)%top]);
if(s2<0) s2=-s2;
ans = s2;
}
}
S = ans;
wl(ans);
}
fwrite(outbuf,1,outpos,stdout);
return 0;
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 57.75 us | 76 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #2 | 42.955 ms | 244 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #3 | 40.067 ms | 240 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #4 | 37.021 ms | 240 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #5 | 3 s | 3 MB + 836 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #6 | 3 s | 4 MB + 336 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #7 | 3 s | 4 MB + 336 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #8 | 3 s | 4 MB + 912 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #9 | 3 s | 3 MB + 832 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #10 | 3 s | 4 MB + 316 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #11 | 3 s | 4 MB + 8 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #12 | 3 s | 4 MB + 764 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #13 | 3 s | 5 MB + 1008 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #14 | 3 s | 6 MB + 156 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #15 | 3 s | 7 MB + 520 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #16 | 3 s | 6 MB + 908 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #17 | 3 s | 7 MB + 32 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #18 | 3 s | 7 MB + 192 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #19 | 3 s | 7 MB + 400 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #20 | 3 s | 7 MB + 520 KB | Time Limit Exceeded | Score: 0 | 显示更多 |