// NOI2017 分身术 - convex layers + materialize exposed chain + Graham scan (correctness-first).
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
static const int MAXN = 100005;
static ll X[MAXN], Y[MAXN];
static inline ll crs3(int a,int b,int c){ return (X[b]-X[a])*(Y[c]-Y[b])-(Y[b]-Y[a])*(X[c]-X[b]); }
static inline ll cross2(int a,int b){ return X[a]*Y[b]-Y[a]*X[b]; }
static int K;
static vector<int> vert[130];
static int h[130];
static vector<ll> pref[130];
static int layer_of[MAXN], pos_of[MAXN];
static int loLen[130];
static vector<pair<int,int>> dels;
static int n, m;
static void collectDeleted(int d, int lo, int hi, vector<int>& out){
out.clear();
int hd = h[d];
for(auto& pr : dels){
if(pr.first != d) continue;
int p = pr.second;
if(lo <= p && p <= hi) out.push_back(p);
if(lo <= p+hd && p+hd <= hi) out.push_back(p+hd);
}
sort(out.begin(), out.end());
out.erase(unique(out.begin(), out.end()), out.end());
}
// append exposed chain (surviving layer-d2 f<0 + recursive dips) between anchors A,B (excluding A,B).
// A,B are points (indices into global X/Y). d2 = layer whose f<0 we consider.
static void buildArc(int d2, int lo, int hi, int anchorL, int anchorR, vector<int>& out);
// returns 1 if found (fa,fb set), 0 if empty, -1 if fallback needed
static int findArcFast(int A, int B, int d2, int& fa, int& fb){
int h2 = h[d2];
if(h2 < 3) return -1;
int LL = loLen[d2];
auto g = [&](int t){ return crs3(A, B, vert[d2][t % h2]); };
auto maxOn = [&](int lo,int hi){ int Ol=lo,Or=hi,l=lo,r=hi; while(r-l>2){ int m1=l+(r-l)/3, m2=r-(r-l)/3; if(g(m1)<g(m2)) l=m1; else r=m2; } int e=l; for(int t=l;t<=r;t++) if(g(t)>g(e)) e=t; if(g(Ol)>g(e)) e=Ol; if(g(Or)>g(e)) e=Or; return e; };
auto minOn = [&](int lo,int hi){ int Ol=lo,Or=hi,l=lo,r=hi; while(r-l>2){ int m1=l+(r-l)/3, m2=r-(r-l)/3; if(g(m1)>g(m2)) l=m1; else r=m2; } int e=l; for(int t=l;t<=r;t++) if(g(t)<g(e)) e=t; if(g(Ol)<g(e)) e=Ol; if(g(Or)<g(e)) e=Or; return e; };
int M = maxOn(0, LL-1);
if(LL < h2){ int M2 = maxOn(LL, h2-1); if(g(M2) > g(M)) M = M2; }
int m = minOn(0, LL-1);
if(LL < h2){ int m2 = minOn(LL, h2-1); if(g(m2) < g(m)) m = m2; }
ll gM = g(M), gm = g(m);
if(gM < 0){ fa = 0; fb = h2-1; return 1; }
if(gm > 0) return 0;
if(gM == 0 || gm == 0) return -1;
int start=M, end=m; if(end<start) end+=h2;
int lo=start, hi=end;
while(lo<hi){ int mid=(lo+hi)>>1; if(g(mid)>=0) lo=mid+1; else hi=mid; }
fa = lo % h2;
start=m; end=M; if(end<start) end+=h2;
lo=start; hi=end;
while(lo<hi){ int mid=(lo+hi)>>1; if(g(mid)<0) lo=mid+1; else hi=mid; }
fb = (lo-1+h2) % h2;
return 1;
}
static int findArcSlow(int A, int B, int d2, int& fa, int& fb){
int h2 = h[d2];
int e0 = -1; bool anyNon = false;
for(int t=0;t<h2;t++){ if(crs3(A,B,vert[d2][t]) < 0){ if(e0<0)e0=t; } else anyNon = true; }
if(e0 == -1) return 0;
if(!anyNon){ fa = 0; fb = h2-1; return 1; }
fa = e0; fb = e0;
for(int st=0; st<h2 && crs3(A,B,vert[d2][(fb+1)%h2])<0; st++) fb=(fb+1)%h2;
for(int st=0; st<h2 && crs3(A,B,vert[d2][(fa-1+h2)%h2])<0; st++) fa=(fa-1+h2)%h2;
return 1;
}
static void buildExposed(int d, int A, int B, vector<int>& out){
int d2 = d+1;
if(d2 >= K) return;
int h2 = h[d2];
int fa, fb;
int r = findArcFast(A, B, d2, fa, fb);
if(r == 0) return;
if(r == -1){ r = findArcSlow(A, B, d2, fa, fb); if(r == 0) return; }
int lo = fa, hi = (fb >= fa) ? fb : fb + h2;
buildArc(d2, lo, hi, A, B, out);
}
static void buildArc(int d2, int lo, int hi, int A, int B, vector<int>& out){
int h2 = h[d2];
vector<int> dp; collectDeleted(d2, lo, hi, dp);
if(dp.empty()){
for(int t=lo;t<=hi;t++) out.push_back(vert[d2][t % h2]);
return;
}
int cur = lo;
int i = 0;
while(i < (int)dp.size()){
int p = dp[i], q = p;
while(i+1 < (int)dp.size() && dp[i+1] == q+1) q = dp[++i];
for(int t=cur;t<=p-1;t++) out.push_back(vert[d2][t % h2]);
buildExposed(d2, A, B, out);
cur = q+1;
i++;
}
for(int t=cur;t<=hi;t++) out.push_back(vert[d2][t % h2]);
}
// convex chain cross-sum from A to B through the exposed set E (outside chord AB)
static ll convexChain(int A, vector<int>& E, int B){
if(E.empty()) return cross2(A, B);
static vector<int> pts; pts.clear();
pts = E; pts.push_back(A); pts.push_back(B);
sort(pts.begin(), pts.end(), [](int a,int b){ return X[a]!=X[b]?X[a]<X[b]:Y[a]<Y[b]; });
pts.erase(unique(pts.begin(), pts.end()), pts.end());
if(pts.size() < 3) return cross2(A, B);
static int stk[MAXN*2]; int top=0;
for(int idx:pts){ while(top>=2 && crs3(stk[top-2],stk[top-1],idx)<=0) top--; stk[top++]=idx; }
int lower=top;
for(int t=(int)pts.size()-2;t>=0;t--){ int idx=pts[t]; while(top>lower && crs3(stk[top-2],stk[top-1],idx)<=0) top--; stk[top++]=idx; }
top--;
int iA=-1, iB=-1;
for(int i=0;i<top;i++){ if(stk[i]==A) iA=i; if(stk[i]==B) iB=i; }
ll s = 0;
if(stk[(iA+1)%top] == B){
for(int k=iA; ; k=(k-1+top)%top){
int nxt=(k-1+top)%top;
s += cross2(stk[k], stk[nxt]);
if(stk[nxt]==B) break;
}
} else {
for(int k=iA; ; k=(k+1)%top){
int nxt=(k+1)%top;
s += cross2(stk[k], stk[nxt]);
if(stk[nxt]==B) break;
}
}
return s;
}
static char inbuf[1<<22]; static size_t inpos=0, inlen=0;
static inline char gc(){ if(inpos>=inlen){ inlen=fread(inbuf,1,sizeof(inbuf),stdin); inpos=0; if(inlen==0)return 0; } return inbuf[inpos++]; }
static inline ll rd(){ char c; while((c=gc()) && (c<'0'||c>'9') && c!='-'); if(c==0) return 0; int s=1; if(c=='-'){s=-1;c=gc();} ll v=0; while(c>='0'&&c<='9'){v=v*10+(c-'0');c=gc();} return s*v; }
static char outbuf[1<<22]; static size_t outpos=0;
static inline void wl(ll v){ if(outpos>(1<<22)-64){fwrite(outbuf,1,outpos,stdout);outpos=0;} if(v==0){outbuf[outpos++]='0';outbuf[outpos++]='\n';return;} char t[32];int z=0; if(v<0){outbuf[outpos++]='-';v=-v;} while(v){t[z++]='0'+(v%10);v/=10;} while(z)outbuf[outpos++]=t[--z]; outbuf[outpos++]='\n'; }
int main(){
n = (int)rd(); m = (int)rd();
for(int i=0;i<n;i++){ X[i]=rd(); Y[i]=rd(); layer_of[i]=-1; }
{
vector<char> used(n,0);
int rem = n; K = 0;
while(rem >= 3 && K < 120){
vector<int> cur;
for(int i=0;i<n;i++) if(!used[i]) cur.push_back(i);
sort(cur.begin(), cur.end(), [](int a,int b){ return X[a]!=X[b]?X[a]<X[b]:Y[a]<Y[b]; });
int sz = cur.size();
vector<int> lo;
for(int idx:cur){ while(lo.size()>=2 && crs3(lo[lo.size()-2],lo.back(),idx)<=0) lo.pop_back(); lo.push_back(idx); }
vector<int> up;
for(int t=sz-1;t>=0;t--){ int idx=cur[t]; while(up.size()>=2 && crs3(up[up.size()-2],up.back(),idx)<=0) up.pop_back(); up.push_back(idx); }
vector<int> H = lo;
for(int t=1;t<(int)up.size()-1;t++) H.push_back(up[t]);
if(H.size() < 3) break;
vert[K]=H; h[K]=H.size(); loLen[K]=lo.size();
pref[K].assign(2*h[K]+2, 0);
for(int t=0;t<2*h[K]+1;t++) pref[K][t+1] = pref[K][t] + cross2(H[t % h[K]], H[(t+1)%h[K]]);
for(int t=0;t<h[K];t++){ layer_of[H[t]]=K; pos_of[H[t]]=t; used[H[t]]=1; }
K++; rem -= H.size();
}
if(rem>0){
vector<int> rest;
for(int i=0;i<n;i++) if(!used[i]) rest.push_back(i);
sort(rest.begin(), rest.end(), [](int a,int b){ return X[a]!=X[b]?X[a]<X[b]:Y[a]<Y[b]; });
vert[K]=rest; h[K]=rest.size(); loLen[K]=rest.size();
pref[K].assign(2*h[K]+2, 0);
for(int t=0;t<2*h[K]+1;t++) pref[K][t+1] = pref[K][t] + cross2(rest[t % h[K]], rest[(t+1)%h[K]]);
for(int t=0;t<h[K];t++){ layer_of[rest[t]]=K; pos_of[rest[t]]=t; }
K++;
}
}
ll S = -1;
dels.reserve(110);
for(int q=0;q<m;q++){
int k = (int)rd();
dels.clear();
for(int j=0;j<k;j++){
ll c = rd(); ll v = S + c; v %= n; if(v<0) v += n;
int id = (int)v;
if(layer_of[id] >= 0) dels.push_back({layer_of[id], pos_of[id]});
}
int h0 = h[0];
vector<int> del0;
for(auto& pr : dels) if(pr.first==0) del0.push_back(pr.second);
sort(del0.begin(), del0.end());
del0.erase(unique(del0.begin(), del0.end()), del0.end());
ll ans = 0;
if(del0.empty()){
ans = pref[0][h0];
} else {
// group deleted L0 positions into maximal cyclic runs
int cnt = del0.size();
vector<pair<int,int>> runs;
{
int i = 0;
while(i < cnt){
int p = del0[i], q = p;
while(i+1 < cnt && del0[i+1] == q+1) q = del0[++i];
runs.push_back({p, q});
i++;
}
}
// merge cyclic wrap: first run starts at 0 and last run ends at h0-1
if(runs.size() >= 2 && runs[0].first == 0 && runs.back().second == h0-1){
vector<pair<int,int>> merged;
merged.push_back({runs.back().first, runs[0].second});
for(int j=1; j<(int)runs.size()-1; j++) merged.push_back(runs[j]);
runs = merged;
}
for(auto& pr : runs){
int p = pr.first, q = pr.second;
int A = vert[0][(p-1+h0) % h0];
int B = vert[0][(q+1) % h0];
int lo = p-1; if(lo < 0) lo += h0;
int hi = q+1; if(hi <= lo) hi += h0;
ll oldArc = pref[0][hi] - pref[0][lo];
static vector<int> E; E.clear();
buildExposed(0, A, B, E);
ll newChain = convexChain(A, E, B);
ans += newChain - oldArc;
}
ans += pref[0][h0];
}
if(ans < 0) ans = -ans;
S = ans;
wl(ans);
}
fwrite(outbuf,1,outpos,stdout);
return 0;
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 60.96 us | 72 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #2 | 60.782 ms | 316 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #3 | 57.814 ms | 316 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #4 | 51.808 ms | 328 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #5 | 281.924 ms | 7 MB + 832 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #6 | 286.241 ms | 8 MB + 584 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #7 | 285.96 ms | 8 MB + 580 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #8 | 289.845 ms | 9 MB + 108 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #9 | 243.253 ms | 8 MB + 24 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #10 | 246.297 ms | 8 MB + 692 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #11 | 270.662 ms | 8 MB + 404 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #12 | 393.785 ms | 9 MB + 180 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #13 | 3 s | 7 MB + 316 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #14 | 3 s | 7 MB + 500 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #15 | 3 s | 9 MB + 112 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #16 | 3 s | 8 MB + 112 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #17 | 3 s | 8 MB + 448 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #18 | 3 s | 8 MB + 612 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #19 | 3 s | 8 MB + 820 KB | Time Limit Exceeded | Score: 0 | 显示更多 |
| Testcase #20 | 3 s | 8 MB + 996 KB | Time Limit Exceeded | Score: 0 | 显示更多 |