提交记录 5321


用户 题目 状态 得分 用时 内存 语言 代码长度
backup_noob 1002i. 【模板题】多项式乘法 Accepted 100 67.83 ms 4684 KB C++ 1.07 KB
提交时间 评测时间
2018-08-17 11:01:07 2020-08-01 00:15:37
#include<cstdio>
#include<algorithm>
#include<iostream>
using namespace std;
const int N=4e5+5,p=998244353;
int n,m,L,inv,a[N],b[N],R[N];
inline int pow(int x,int y){
    int ans=1;while(y){if(y&1)ans=1ll*ans*x%p;x=1ll*x*x%p;y>>=1;}
    return ans;
}
void FFT(int *A,int o){
    for(int i=0;i<n;++i)if(R[i]>i)swap(A[R[i]],A[i]);
    for(int i=1;i<n;i<<=1){
        int wn=pow(3,(p-1)/(i<<1)),a,b,w;
        for(int j=0;j<n;j+=(i<<1)){
            w=1;for(int k=0;k<i;++k,w=1ll*w*wn%p){
                a=A[j+k],b=1ll*A[i+j+k]*w%p;
                A[j+k]=(a+b)%p;A[i+j+k]=(a-b+p)%p;
            }
        }
    }
    if(o==-1){
        reverse(A+1,A+n);
        for(int i=0;i<n;++i)A[i]=1ll*A[i]*inv%p;
    }
}
int main(){
    ios::sync_with_stdio(false);
    cin>>n>>m;
    for(int i=0;i<=n;++i)cin>>a[i];
    for(int i=0;i<=m;++i)cin>>b[i];
    m+=n;for(n=1;n<=m;n<<=1)++L;inv=pow(n,p-2);
    for(int i=1;i<n;++i)R[i]=((i&1)<<(L-1))|(R[i>>1]>>1);
    FFT(a,1);FFT(b,1);for(int i=0;i<n;++i)a[i]=1ll*a[i]*b[i]%p;
    FFT(a,-1);
    for(int i=0;i<=m;++i)cout<<a[i]<<' ';
    cout<<endl;return 0;
}

CompilationN/AN/ACompile OKScore: N/A

Subtask #1 Testcase #142.93 us72 KBAcceptedScore: 0

Subtask #1 Testcase #267.624 ms4 MB + 508 KBAcceptedScore: 100

Subtask #1 Testcase #331.378 ms1 MB + 872 KBAcceptedScore: 0

Subtask #1 Testcase #431.357 ms1 MB + 860 KBAcceptedScore: 0

Subtask #1 Testcase #543.95 us72 KBAcceptedScore: 0

Subtask #1 Testcase #643.17 us72 KBAcceptedScore: 0

Subtask #1 Testcase #742.68 us72 KBAcceptedScore: 0

Subtask #1 Testcase #863.167 ms4 MB + 240 KBAcceptedScore: 0

Subtask #1 Testcase #963.212 ms4 MB + 240 KBAcceptedScore: 0

Subtask #1 Testcase #1058.716 ms3 MB + 996 KBAcceptedScore: 0

Subtask #1 Testcase #1167.83 ms4 MB + 588 KBAcceptedScore: 0

Subtask #1 Testcase #1264.365 ms3 MB + 468 KBAcceptedScore: 0

Subtask #1 Testcase #1341.71 us72 KBAcceptedScore: 0


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