代码

#define N (256 << (20 - 2))

int A[N];

int main() {
	int sum = 0;
	int x = 0;
	for (int i = 0; i < N / 4; i++) {
		sum += A[x];
		x = x + (1 << 19);
		x = x & (N - 1);
	}
	return sum;
}

评测结果