提交记录 7227


用户 题目 状态 得分 用时 内存 语言 代码长度
HowNegative 1002i. 【模板题】多项式乘法 Accepted 100 24.326 ms 19472 KB C++ 2.47 KB
提交时间 评测时间
2019-01-08 20:40:18 2020-08-01 01:01:32
#include<cstdio>
#include<algorithm>
#include<ctype.h>
#include<string.h>
#include<math.h>

using namespace std;
#define ll long long

static char buf[1<<19], *s=buf;
inline void read(int &x) {
    while(isspace(*s)) ++s;
    x=*s++^'0';
    while(isdigit(*s)) x=x*10+(*s++^'0');
}
char obuf[1<<20], *ooh=obuf;
inline void print(int x) {
    static int buf[30], cnt;
    if (x==0) *ooh++='0';
    else {
        for (cnt=0; x; x/=10) buf[++cnt]=x%10+48;
        while(cnt) *ooh++=buf[cnt--];
    }
}

const double Pi = acos(-1);
const int N = 1<<18;
int n, m;
struct cp{
	double a, b;
	inline void operator +=(const cp &rhs){ a+=rhs.a, b+=rhs.b;}
	inline cp operator +(const cp &rhs)const{ return (cp){a+rhs.a, b+rhs.b};}
	inline cp operator -(const cp &rhs)const{ return (cp){a-rhs.a, b-rhs.b};}
	inline cp operator *(const cp &rhs)const{ return (cp){a*rhs.a-b*rhs.b, a*rhs.b+b*rhs.a};}
	inline cp operator *(const double rhs)const{ return (cp){a*rhs, b*rhs};}
	inline cp operator ~()const{ return (cp){a, -b};}
} f[N], g[N], w[N];
inline int Get(int x){ int n=1; while(n<=x) n<<=1; return n;}
inline void DFT_(cp *f, int n){
	for(register int i=0, j=0; i<n; ++i){
		if(i>j) swap(f[i], f[j]);
		for(register int k=n>>1; (j^=k)<k; k>>=1);
	}
	for(register int i=1; i<n; i<<=1) for(register int j=0; j<n; j+=i<<1)
		for(register int k=j; k<j+i; ++k){
			cp t=w[i+k-j]*f[k+i];
			f[k+i]=f[k]-t, f[k]+=t;
		}
}
inline void DFT(cp *f, int n){
	if(n==1) return;
	n>>=1;
	static cp a[N];
	for(register int i=0; i<n; ++i) a[i]=(cp){f[i<<1].a, f[i<<1|1].a};
	DFT_(a, n);
	for(register int i=0; i<n; ++i){
		cp q=~a[(n-i)&(n-1)], x=(a[i]+q)*.5, y=(a[i]-q)*(cp){0, -.5}, t=y*w[n+i];
		f[i]=x+t, f[n+i]=x-t;
	}
}
inline void IDFT(cp *f, int n){
	if(n==1) return;
	reverse(f+1, f+n), n>>=1;
	static cp a[N];
	for(register int i=0; i<n; ++i)
		a[i]=(f[i]+f[i+n])*.5 + (f[i]-f[i+n])*(cp){0, .5}*w[n+i];
	DFT_(a, n);
	double k=1./n;
	for(register int i=0; i<n; ++i) f[i<<1]=(cp){a[i].a*k, 0}, f[i<<1|1]=(cp){a[i].b*k, 0};
}
int main() {
    fread(s, 1, 1<<19, stdin);
	read(n), read(m), ++n, ++m;
	for(int i=0, x; i<n; ++i) read(x), f[i].a=x;
	for(int i=0, x; i<m; ++i) read(x), g[i].a=x;
	int l=Get(n+m-2);
	for(int i=1; i<l; i<<=1){
		w[i]=(cp){1, 0};
		for(int j=1; j<i; ++j)
			w[i+j]=((j&31)==1?(cp){cos(Pi*j/i), sin(Pi*j/i)}:w[i+j-1]*w[i+1]);
	}
	DFT(f, l), DFT(g, l);
	for(int i=0; i<l; ++i) f[i]=f[i]*g[i];
	IDFT(f, l);
	for(int i=0; i<n+m-1; ++i) print((int)(f[i].a+0.5)), *ooh++=' ';
	return fwrite(obuf, 1, ooh - obuf, stdout), 0;
}

CompilationN/AN/ACompile OKScore: N/A

Subtask #1 Testcase #18.56 us40 KBAcceptedScore: 0

Subtask #1 Testcase #223.935 ms18 MB + 880 KBAcceptedScore: 100

Subtask #1 Testcase #39.307 ms8 MB + 792 KBAcceptedScore: 0

Subtask #1 Testcase #49.394 ms8 MB + 772 KBAcceptedScore: 0

Subtask #1 Testcase #510.06 us40 KBAcceptedScore: 0

Subtask #1 Testcase #68.68 us40 KBAcceptedScore: 0

Subtask #1 Testcase #78.61 us40 KBAcceptedScore: 0

Subtask #1 Testcase #823.126 ms18 MB + 504 KBAcceptedScore: 0

Subtask #1 Testcase #922.828 ms18 MB + 504 KBAcceptedScore: 0

Subtask #1 Testcase #1022.313 ms18 MB + 68 KBAcceptedScore: 0

Subtask #1 Testcase #1124.326 ms19 MB + 16 KBAcceptedScore: 0

Subtask #1 Testcase #1219.459 ms17 MB + 168 KBAcceptedScore: 0

Subtask #1 Testcase #137.41 us32 KBAcceptedScore: 0


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