代码

int plus(int a, int b)
{
int t = 0;
for (int j = 1; j <= 100000000; j++)
for (int i = 1; i <= 100000000; i++) {
t += (long long) i * i % 124335483;
}
a += t % 7;
a -= t % 7;
	return a + b;
}

评测结果