/*
Author: QAQ Automaton
Lang: C++
Prog: robot.cpp
Mail: lk@qaq-am.com
Blog: https://www.qaq-am.com/
*/
#include<bits/stdc++.h>
#define int long long
#define debug(...) fprintf(stderr,__VA_ARGS__)
#define DEBUG printf("Passing [%s] in LINE %d\n",__FUNCTION__,__LINE__)
#define Debug debug("Passing [%s] in LINE %d\n",__FUNCTION__,__LINE__)
#define all(x) x.begin(),x.end()
#define x first
#define y second
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
#define inf 0x3f3f3f3f3f3f3f3f3f3f3f3f3f3f3f3f
const double eps=1e-8;
const double pi=acos(-1.0);
template<class T>int chkmin(T &a,T b){return a>b?a=b,1:0;}
template<class T>int chkmax(T &a,T b){return a<b?a=b,1:0;}
template<class T>T sqr(T a){return a*a;}
template<class T>T mmin(T a,T b){return a<b?a:b;}
template<class T>T mmax(T a,T b){return a>b?a:b;}
template<class T>T aabs(T a){return a<0?-a:a;}
template<class T>int dcmp(T a,T b){return a>b;}
template<int *a>int cmp_a(int x,int y){return a[x]<a[y];}
#define min mmin
#define max mmax
#define abs aabs
namespace io {
const int SIZE = (1 << 21) + 1;
char ibuf[SIZE], *iS, *iT, obuf[SIZE], *oS = obuf, *oT = oS + SIZE - 1, c, qu[55]; int f, qr;
// getchar
#define gc() (iS == iT ? (iT = (iS = ibuf) + fread (ibuf, 1, SIZE, stdin), (iS == iT ? EOF : *iS ++)) : *iS ++)
// print the remaining part
inline void flush () {
fwrite (obuf, 1, oS - obuf, stdout);
oS = obuf;
}
// putchar
inline void putc (char x) {
*oS ++ = x;
if (oS == oT) flush ();
}
// input a signed integer
inline bool read (signed &x) {
for (f = 1, c = gc(); c < '0' || c > '9'; c = gc()) if (c == '-') f = -1;else if(c==EOF)return 0;
for (x = 0; c <= '9' && c >= '0'; c = gc()) x = x * 10 + (c & 15); x *= f;
return 1;
}
inline bool read (long long &x) {
for (f = 1, c = gc(); c < '0' || c > '9'; c = gc()) if (c == '-') f = -1;else if(c==EOF)return 0;
for (x = 0; c <= '9' && c >= '0'; c = gc()) x = x * 10 + (c & 15); x *= f;
return 1;
}
inline bool read (char &x) {
x=gc();
return x!=EOF;
}
inline bool read(char *x){
while((*x=gc())=='\n' || *x==' '||*x=='\r')if(*x==EOF)return 0;
while(!(*x=='\n'||*x==' '||*x=='\r'))*(++x)=gc();
*x=0;
return 1;
}
template<typename A,typename ...B>
inline bool read(A &x,B &...y){
return read(x)&&read(y...);
}
// print a signed integer
inline bool write (signed x) {
if (!x) putc ('0'); if (x < 0) putc ('-'), x = -x;
while (x) qu[++ qr] = x % 10 + '0', x /= 10;
while (qr) putc (qu[qr --]);
return 0;
}
inline bool write (long long x) {
if (!x) putc ('0'); if (x < 0) putc ('-'), x = -x;
while (x) qu[++ qr] = x % 10 + '0', x /= 10;
while (qr) putc (qu[qr --]);
return 0;
}
inline bool write (char x) {
putc(x);
return 0;
}
inline bool write(const char *x){
while(*x){putc(*x);++x;}
return 0;
}
inline bool write(char *x){
while(*x){putc(*x);++x;}
return 0;
}
template<typename A,typename ...B>
inline bool write(A x,B ...y){
return write(x)||write(y...);
}
//no need to call flush at the end manually!
struct Flusher_ {~Flusher_(){flush();}}io_flusher_;
}
using io :: read;
using io :: putc;
using io :: write;
int f[55][55][105],vis[55][55][105];
int a[55],b[55],ok;
int c[55][55],xc[55],inv[55];
const int p=1000000007;
int dfs(int l,int r,int w){
if(l>r)return 1;
if(!w)return 0;
if(vis[l][r][w])return f[l][r][w];
vis[l][r][w]=1;
f[l][r][w]=dfs(l,r,w-1);
if((l&1) == (r&1)){
int mid=(l+r)>>1;
if(a[mid]<=w && w<=b[mid])f[l][r][w]+=dfs(l,mid-1,w)*dfs(mid+1,r,w-1);
if(mid>l && a[mid-1]<=w && w<=b[mid-1])f[l][r][w]+=dfs(l,mid-2,w)*dfs(mid,r,w-1);
if(mid<r && a[mid+1]<=w && w<=b[mid+1])f[l][r][w]+=dfs(l,mid,w)*dfs(mid+2,r,w-1);
}
else{
int mid=(l+r)>>1;
if(a[mid]<=w && w<=b[mid])f[l][r][w]+=dfs(l,mid-1,w)*dfs(mid+1,r,w-1);
if(mid<r && a[mid+1]<=w && w<=b[mid+1])f[l][r][w]+=dfs(l,mid,w)*dfs(mid+2,r,w-1);
}
return f[l][r][w]%=p;
}
signed main(){
int n;
read(n);
ok=1;
for(int i=1;i<=n;++i){
read(a[i],b[i]);
if(b[i]>100)ok=0;
}
if(ok){
write(dfs(1,n,100),'\n');
}
else{
dfs(1,n,n);
for(int i=0;i<=n;++i){
c[i][0]=c[i][i]=1;
for(int j=1;j<i;++j)c[i][j]=(c[i-1][j]+c[i-1][j-1])%p;
}
xc[0]=1;
inv[0]=1;
inv[1]=1;
for(int i=2;i<=n;++i)inv[i]=(p-p/i)*inv[p%i]%p;
for(int i=1;i<=n;++i)xc[i]=xc[i-1]*(1000000001-i)%p*inv[i]%p;
int ans=0;
for(int i=1;i<=n;++i){
f[1][n][i]=(f[1][n][i]%p+p)%p;
ans=(ans+xc[i]*f[1][n][i])%p;
for(int j=i+1;j<=n;++j)f[1][n][j]-=c[j][i]*f[1][n][i]%p;
}
write(ans,'\n');
}
return 0;
}
| Compilation | N/A | N/A | Compile OK | Score: N/A | 显示更多 |
| Testcase #1 | 41.62 us | 120 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #2 | 45.85 us | 100 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #3 | 49.05 us | 124 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #4 | 44.07 us | 124 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #5 | 230.91 us | 864 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #6 | 248.03 us | 852 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #7 | 210.28 us | 840 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #8 | 166.33 us | 212 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #9 | 143.3 us | 200 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #10 | 166.07 us | 212 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #11 | 165.33 us | 580 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #12 | 212.88 us | 708 KB | Accepted | Score: 5 | 显示更多 |
| Testcase #13 | 46.72 us | 84 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #14 | 46.93 us | 84 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #15 | 45.96 us | 84 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #16 | 84.65 us | 136 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #17 | 83.19 us | 140 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #18 | 105.47 us | 164 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #19 | 108.24 us | 168 KB | Wrong Answer | Score: 0 | 显示更多 |
| Testcase #20 | 179.78 us | 216 KB | Wrong Answer | Score: 0 | 显示更多 |