提交记录 4131


用户 题目 状态 得分 用时 内存 语言 代码长度
mangoyang noi18c. 【NOI2018】你的名字 Time Limit Exceeded 56 4 s 549564 KB C++ 3.49 KB
提交时间 评测时间
2018-07-18 21:09:46 2020-07-31 22:30:42
/*pragram by mangoyang*/
#include<cstdio>
#include<algorithm>
#include<ctype.h>
#include<vector>
#include<cstring>
#define inf (0x7f7f7f7f)
#define Max(a, b) ((a) > (b) ? (a) : (b))
#define Min(a, b) ((a) < (b) ? (a) : (b))
typedef long long ll;
using namespace std;
template <class T>
inline void read(T &x){
    int f = 0, ch = 0; x = 0;
    for(; !isdigit(ch); ch = getchar()) if(ch == '-') f = 1;
    for(; isdigit(ch); ch = getchar()) x = x * 10 + ch - 48;
    if(f) x = -x;
}
const int N = 3500005, MAXN = 1500005;
char s[N]; int rt[N], n;
struct SegmentTree{
	int lc[MAXN*25], rc[MAXN*25], sz[MAXN*25], size;
	inline SegmentTree(){ size = 1; }
	inline void ins(int &u, int l, int r, int pos){
		if(!u) u = ++size;
		if(l == r) return (void) (sz[u]++);
		int mid = l + r >> 1; 
		if(pos <= mid) ins(lc[u], l, mid, pos);
		else ins(rc[u], mid + 1, r, pos); 
		sz[u] = sz[lc[u]] + sz[rc[u]];
	}
	inline int merge(int x, int y, int l, int r){
		if(!x || !y) return x + y;
		int mid = l + r >> 1, o = ++size;
		if(l == r) sz[o] = sz[x] + sz[y];
		else{
			lc[o] = merge(lc[x], lc[y], l, mid);
			rc[o] = merge(rc[x], rc[y], mid + 1, r);
			sz[o] = sz[lc[o]] + sz[rc[o]];
		}
		return o;
	}
	inline int query(int u, int l, int r, int pos){
		if(!sz[u]) return 0;
		if(l == r) return l;
		int mid = l + r >> 1;
		if(pos <= mid) return query(lc[u], l, mid, pos);
		int rans = query(rc[u], mid + 1, r, pos);
		return rans ? rans : query(lc[u], l, mid, pos);
	}
}Seg;
struct SuffixAutomaton{
	vector<int> g[N], v; ll dep[N];
	int ch[N][26], fa[N], vis[N], tail, size;
	inline SuffixAutomaton(){ size = tail = 1, rt[1] = 1; }
	inline int newnode(int x){ return dep[++size] = x, size; }
    inline void ins(int c, int ff, int pos){
        int p = tail, np = newnode(dep[p] + 1);
        if(ff) v.push_back(np); else Seg.ins(rt[np], 1, n, pos);
        for(; p && !ch[p][c]; p = fa[p]) ch[p][c] = np;
        if(!p) return (void) (fa[np] = 1, tail = np);
        int q = ch[p][c];
        if(dep[q] == dep[p] + 1) fa[np] = q;
        else{
            int nq = newnode(dep[p] + 1);
            fa[nq] = fa[q], fa[np] = fa[q] = nq;
            if(ff) rt[nq] = rt[q];
            for(int i = 0; i < 26; i++) ch[nq][i] = ch[q][i];
            for(; p && ch[p][c] == q; p = fa[p]) ch[p][c] = nq;	
        }tail = np;
    }
	inline void addedge(){
		for(int i = 2; i <= size; i++) g[fa[i]].push_back(i);
	}
	inline void dfs(int u){
		for(int i = 0; i < g[u].size(); i++){
			int v = g[u][i];
			dfs(v), rt[u] = Seg.merge(rt[u], rt[v], 1, n);	
		}
	}
	inline void prepare(char *s){
		for(int i = 0; i < n; i++) ins(s[i] - 'a', 0, i + 1);
		addedge(), dfs(1);
	}	
	inline ll calc(char *s, int l, int r){
		tail = 1; v.clear(); 
		ll len = strlen(s), ans = 0, all = 0;
		for(int i = 0; i < len; i++) ins(s[i] - 'a', 1, 0);
		for(int i = 0; i < v.size(); i++){
			int u = v[i];
			for(int p = u; p > 1; p = fa[p]) {
				if(vis[p]) break; int OK = 0;
				all += dep[p] - dep[fa[p]], vis[p] = 1;
				if(rt[p]){
					if(OK)
						{ ans += dep[p] - dep[fa[p]]; continue; }
					int mxlen = Seg.query(rt[p], 1, n, r) - l + 1;
					if(mxlen > dep[fa[p]]) 
						ans += Min(dep[p], mxlen) - dep[fa[p]];
					if(mxlen >= dep[p]) OK = 1;
				}
			}
		}
		for(int i = 0; i < v.size(); i++){
			int u = v[i];
			for(int p = u; p > 1; p = fa[p]){
				if(!vis[p]) break; vis[p] = 0;
			}
		}
		return all - ans;
	}	
}van;
int main(){
	scanf("%s", s); n = strlen(s);
	int Q; read(Q), van.prepare(s);
	while(Q--){
		int l, r;
		scanf("%s", s), read(l), read(r);
		printf("%lld\n", van.calc(s, l, r));
	}
}

CompilationN/AN/ACompile OKScore: N/A

Testcase #119.811 ms87 MB + 224 KBAcceptedScore: 4

Testcase #224.097 ms87 MB + 612 KBAcceptedScore: 4

Testcase #324.863 ms87 MB + 892 KBAcceptedScore: 4

Testcase #4156.046 ms172 MB + 588 KBAcceptedScore: 4

Testcase #5150.098 ms169 MB + 884 KBAcceptedScore: 4

Testcase #6653.627 ms497 MB + 260 KBAcceptedScore: 4

Testcase #7654.771 ms497 MB + 284 KBAcceptedScore: 4

Testcase #81.079 s167 MB + 556 KBAcceptedScore: 4

Testcase #9225.966 ms164 MB + 416 KBAcceptedScore: 4

Testcase #102.341 s256 MB + 624 KBAcceptedScore: 4

Testcase #11522.996 ms256 MB + 860 KBAcceptedScore: 4

Testcase #124 s343 MB + 464 KBTime Limit ExceededScore: 0

Testcase #13876.6 ms350 MB + 700 KBAcceptedScore: 4

Testcase #144 s410 MB + 928 KBTime Limit ExceededScore: 0

Testcase #151.271 s444 MB + 708 KBAcceptedScore: 4

Testcase #164 s476 MB + 436 KBTime Limit ExceededScore: 0

Testcase #171.694 s536 MB + 700 KBAcceptedScore: 4

Testcase #184 s296 MB + 848 KBTime Limit ExceededScore: 0

Testcase #194 s354 MB + 32 KBTime Limit ExceededScore: 0

Testcase #204 s412 MB + 444 KBTime Limit ExceededScore: 0

Testcase #214 s476 MB + 288 KBTime Limit ExceededScore: 0

Testcase #224 s474 MB + 116 KBTime Limit ExceededScore: 0

Testcase #234 s474 MB + 228 KBTime Limit ExceededScore: 0

Testcase #244 s475 MB + 644 KBTime Limit ExceededScore: 0

Testcase #254 s475 MB + 204 KBTime Limit ExceededScore: 0


Judge Duck Online | 评测鸭在线
Server Time: 2026-04-14 02:57:46 | Loaded in 1 ms | Server Status
个人娱乐项目,仅供学习交流使用 | 捐赠