代码

#define N (256 << (20 - 2))

int A[N];

int main() {
	for (int i = 0; i < N; i++) {
		A[i] = i ^ (i >> 5);
	}
	int sum = 0;
	int x = 233;
	for (int i = 0; i < N; i++) {
		sum += A[x & (N - 1)];
		x ^= x << 13;
		x ^= x >> 17;
		x ^= x << 5;
	}
	return sum;
}

评测结果