#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int N=1000010;
char s[N];
int n,sa[N],rk[N<<1],oldrk[N<<1],id[N],px[N],cnt[N]; //px[i]=rk[id[i]](用于排序的数组所以叫px)
int main()
{
int i,m,p,w;
scanf("%s",s+1);
n=strlen(s+1);
m=max(n,300);
for (i=1;i<=n;++i) ++cnt[rk[i]=s[i]];
for (i=1;i<=m;++i) cnt[i]+=cnt[i-1];
for (i=n;i>=1;--i) sa[cnt[rk[i]]--]=i;
for (w=1;w<n;w<<=1)
{
for (p=0,i=n;i>n-w;--i) id[++p]=i;
for (i=1;i<=n;++i) if (sa[i]>w) id[++p]=sa[i]-w;
memset(cnt,0,sizeof(cnt));
for (i=1;i<=n;++i) ++cnt[px[i]=rk[id[i]]];
for (i=1;i<=m;++i) cnt[i]+=cnt[i-1];
for (i=n;i>=1;--i) sa[cnt[px[i]]--]=id[i];
swap(rk,id);
for (p=0,i=1;i<=n;++i) rk[sa[i]]=id[sa[i]]==id[sa[i-1]]&&id[sa[i]+w]==id[sa[i-1]+w]?p:++p; //注意这里的id相当于原来的oldrk
}
for (i=1;i<=n;++i) printf("%d ",sa[i]);
return 0;
}